by on April 3, 2020
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The Area under Velocity-Time Graph is = Distance  cover

Lets consider the FIG 5 above

A body start with an initia velocity =u and accelerate to velocity =v with uniform acceleration =a

The graph of the motion is shown in FIG 5 Above

note , AO=u and BE=v

the slope of the Graph=

Therefore Acceleration a= slope of triangle ABC=

The Area under the line AB = Areae of trapezium AOEB  =

Therefore the Area under line AB = distance cover

The Area under Velocity-Time Graph is = Distance cover

. if this body starts from REST , u=0 and point A is now = point O , BC=v

then the Area of the triangle ABC = distance cover = 

if the body moved at uniform velocity only, then u=v, line AC will represent the graph of the motion, 

then distance cover will be area of the rectangle ACEO=

READ distance-time graph

and  Speed-Time Graph

 

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