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on March 31, 2020
MEASUREMENT OF MASS AND WEIGHT GO BACK
MASS
The mass of a substance is a measure of the quantity of matter it contains.
To measure mass it is usually compared with standard Masses
Principle of Mass Measurement
see FIG1
In FIG 1 above M1 is a known mass or standard mass, while M2 is the unknown mass.
At equilibrium when the beam is in perfect horizontal position, this equation is applicable
M1 x L = M2 x A
Therefore M2 =(M1 x L)/A
This is the Principle of measurement for most mass measuring instruments, beam balance or chemical beam balance
Another means of measuring mass is by measuring the weight of the item.
Weight =Mass x g where g is the gravitational constant, g=9.8m/s^2
Therefore, Mass = weight/g
This is how to measure Mass from weight and this is applicable to elastic spring instrument for measuring Mass
Example
If a standard mass of 500g is used in a beam balance as shown in the FIG 1. Given that L=50cm while A=30cm. What is the value of Mass M2 ?
Solution
Remember always do your calculations in SI units.
M1 =500g =0.5kg, L=50cm = 0.5m, A=0.3m
Then M2= 0.5 x 0.5/0.3 = 0.8333kg = 833.3g
WEIGHT MEASUREMENT
Weight can be defined as the earth pull on a substance
The weight W of a substance is directly proportional to extension E on an elastic spring when allow to hang freely on air space, provided the elastic limit is not exceeded.
WɤE, W=KE where k is the elastic constant of the spring.
K can be known by using a known mass to obtain an extension E.
Example
If a known mass of 500g is used for calibration and graduating scale purpose of an instrument designed to measure weight and this mass produce extension of 10cm . What is the value of K for the spring. Hence do a scale graduation for this instrument from 1g to 1kg at 100g interval.
Solution
M=500g =0.5kg
E=10cm=0.1m
W=Mg=0.5 x 9.8 = 4.9N
Where g = gravitational constant or Acceleration due to gavity
W=kE therefore
k=W/E=4.9/0.1 = 49N/m
E=W/k
When Mass=1g=0.001kg, W=0.001x9.8, = 0.0098N, E=0.0098/49m =0.0002m =0.02cm
Mass in g |
weight in N |
Extension E in cm |
1 |
0.0098 |
0.02 |
100 |
0.98 |
2.00 |
200 |
1.96 |
4.00 |
300 |
2.94 |
6.00 |
400 |
3.92 |
8.00 |
500 |
4.9 |
10.00 |
600 |
5.88 |
12.00 |
700 |
6.86 |
14.00 |
800 |
7.84 |
16.00 |
900 |
8.82 |
18.00 |
1000 |
9.8 |
20.00 |
See fig 2
Whenever this instrument read 10cm the MASS is 500g
MEASUREMENT OF TIME
Stop watch, wall clock, and wrist watch are common instruments to measure TIME.
They measure Time in seconds, minutes and hours
60 seconds = 1 minutes
60 minutes = 1 hour
24 hours = 1 day
Example
Convert 1megaseconds to hours and days
Solution
1 megaseconds = 1000000seconds =1000000/60 minutes =16666.67/60 hours = 277.78 hours
= 277.78/24 days = 11.57 days = 11days +13hour +46minute +34seconds
INSTRUMENTS ACCURACY
Reading accuracy of an instrument is the nearest decimal place we can measure with the instrument. It is the uncertainty in the measure quantity.
The accuracy of Vernier caliper is 0.01cm
The accuracy of Meter Rule is 0.1cm
The accuracy of Micrometer Screwgauge is 0.001cm
INSTRUMENT |
ACCURACY |
Vernier caliper Meter Rule Micrometer Screwgauge |
0.01cm 0.1cm 0.001cm |
Posted in: Education
Topics:
measurement of time and mass
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